Carlos Santana could not be much hotter.
Too bad the same can’t be said for his team.
The Cleveland Indians, who open an eight-game homestand tonight against the Seattle Mariners, are coming off a 10-3 win over the Royals on Sunday.
Unfortunately for them, that was just their second win in their last eight games.
After beating the Tigers three straight after the All-Star break, the Indians proceeded to go just 2-6 the rest of the way to wind up 5-6 on their road trip.
They bring a 52-53 record into tonight’s game and are 6½ games behind the Central Division-leading Tigers.
The blame has not been Santana’s.
The switch-hitter has been tearing it up at the plate on the way to earning American League Player of the Week honors.
Santana batted .556 (15-for-27) in the seven-game period ending Sunday, while adding six home runs, 10 RBIs, three doubles, eight runs and five walks.
It is the first time he has received the weekly honor and makes it two straight weeks an Indians has been the recipient. Jason Kipnis won the week prior, marking the first time the Indians have had back-to-back winners since Manny Ramirez and Bartolo Colon in September of 2000.
How good was Santana’s week? He led the majors in average, home runs, hits, runs, total bases (36) and slugging percentage (1.333) and was second in RBIs and on-base percentage (.636).
WHO: Cleveland vs. Seattle
WHERE: Progressive Field
PITCHERS: Bauer (4-5, 3.93 ERA) vs. Iwakuma (8-5, 3.09)
TV/RADIO: SportsTime Ohio; WEOL 930-AM, WTAM 1100-AM, WMMS 100.7-FM